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Do you want to work at home or are you jobless. Today we posting out very helpful post for those who really want to earn in good figure. Being a freelancer can be extremely advantageous and is probably a dream for many designers and developers who are tired of the cubicle lifestyle. Not only do you get to choose only the jobs you are really interested in, you also have total flexibility in terms of time, whom you want to work with, and where you want to work at.
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Freelancer No 1
Find or post a project or post on this platform to get the best bids from a gamut of skilled web designers, copywriters or freelance programmers.
Elance
A popular online portal for freelancers, this is the ultimate place to meet professionals with business, technical and marketing expertise to get work done at an affordable price.
Upwork
The average budget size of a job here is around $5,000! It’s no wonder that this online marketplace is a great asset for both service providers and employers.
Toptal
Toptal is a hiring marketplace for developers of (almost) all programming languages; it provides “A”-level developers who truly skillful in their fields. You can apply as a freelance developer with the possibility of working with top tech companies or a cool startup.
99designs
99Designs is where companies go to get their logos, banners and websites designed. Designers are awarded a pre-determined amount of money if their design is chosen.
Envato Studio
A house for creatives and developers of many fields to find freelance gigs from all over the world. Apply as a service providers and once you are accepted, you can name your price for your service.
Fiverr
Want to test the waters of freelancing? Give Fiverr a shot. Projects go for between $5 and $10, and this is a great place to gain some experience to add to your portfolio.
StackOverflow Careers
StackOverflow is not only a solution-churning site, it also provides job listings of tech companies from all over the world. To apply for the job, you will need a Stack Career Accounts (you’ll need to be invited first).
Dribbble
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Behance Job
Productivity and creativity go hand in hand at the job list section of this site. This exclusive site is known to convert creativity into lucrative services or products to promote unique ideas.
Solution : 1
The HTML5 geolocation API will get you the user's latitude and longitude (assuming they opt in). If you need to get info such as the city, country, or postal code, you'll need to use a reverse-geocoding web service. There are plenty of those out there:
Google
Bing
etc
So take your pick... just make sure to look at the terms & conditions and be sure you won't be in violation once the site goes live.
You should be able to find code samples by googling around a bit, it's a fairly common use case. The steps will be:
Get the user's lat/lng with your existing code.
Make an AJAX (JSONP) call to request the reverse-geocode (use your Geocode provider to figure out what URL to use. eg, for Google it is like this).
Parse the JSON response to extract the info you need (country, city).
Solution : 2
Try this code using the hostip.info service:
$country=file_get_contents('http://api.hostip.info/get_html.php?ip=');
echo $country;
// Reformat the data returned (Keep only country and country abbr.)
$only_country=explode (" ", $country);
echo "Country : ".$only_country[1]." ".substr($only_country[2],0,4);
Solution : 3
MaxMind GeoIP is a good service. They also have a free city-level lookup service.
Question:
I have a cloud function on Parse. When it's called it retrieves a PFObject then adds a relation between that object and the user. This part works fine (Seen towards the end of the function). I'm having trouble getting the query that selects the PFObject to ignore those that the user is already related to
I'm sure i'm just not understanding how the relation query syntax works.
Parse.Cloud.define("NextMedia", function (request, response) {
var LikeRequest = Parse.Object.extend("LikeRequest");
var query = new Parse.Query(LikeRequest);
query.equalTo("completed", false);
console.log("user: " + Parse.User.current().id);
query.notEqualTo("user", Parse.User.current());
// Also only fetch if never been sent before
// HERE SHOULD USE THE BELOW RELATIONSHIP
var innerQuery = new Parse.Query(Parse.User);
innerQuery.exists(Parse.User);
query.matchesQuery("sentTo", innerQuery);
query.ascending("createdAt");
query.first({
success: function (object) {
// Successfully retrieved the object.
console.log("Got 1 object: " + object.get('mediaId'));
// Record that the user has been sent it
var user = Parse.User.current();
var relation = object.relation("sentTo"); // RELATION ADDED HERE
relation.add(user);
object.save();
response.success(object);
},
error: function (error) {
console.log("Error: " + error.code + " " + error.message);
response.error("Error getting next mediaId");
}
});
});
Answer:
I think Kerem has it partially correct but notContained in is not dynamic enough for your case. You need to construct the query from the relation and then use doesNotMatchKeyInQuery to exclude those objects from your outer query.
This stretch:
// Also only fetch if never been sent before
// HERE SHOULD USE THE BELOW RELATIONSHIP
var innerQuery = new Parse.Query(Parse.User);
innerQuery.exists(Parse.User);
query.matchesQuery("sentTo", innerQuery);
Could be changed to:
// Also only fetch if never been sent before
query.notContainedIn("sentTo",[Parse.User.current()])
what about Query Constraints?
If you want to retrieve objects that do not match any of several values you can use notContainedIn
// Finds objects from anyone who is neither Jonathan, Dario, nor Shawn
query.notContainedIn("playerName",
["Jonathan Walsh", "Dario Wunsch", "Shawn Simon"]);
